perimeter of rectangular is 40m.The length of rectangular is 15m.The width of rectangular is......cepat yaa
1. perimeter of rectangular is 40m.The length of rectangular is 15m.The width of rectangular is......cepat yaa
Jawaban:
Perimeter = 2 ( length + width)
40m = 2 length + 2 widht
40m = 2 × 15 + 2 widht
2 widht = 40 - 30
2 widht = 10
widht = 10/2 = 5
perimeter = keliling
length = panjang
widht = lebar
2. (7)The perimeter of a rectangular carpet is 38 m. Its breadth is 7 m.(a) Find its length.(b) Find the area of the rectangular carpet.
Jawab:
a. l = 2,7 m
b. A = 18,9 m²
Penjelasan dengan langkah-langkah:
a. P = 2 (l.b)
38 = 2 (l.7)
38 = 14l
l = 2,7 m
b. A = l.b = 2,7 x 7 = 18,9 m²
3. The perimeter of a rectangular towel is 116 cm. It’s breadth is 10 cm. Find the length of the towel
Jawaban:
L=48 cm
Penjelasan dengan langkah-langkah:
L: length;B:breadth;p: perimeter
p=2(L+B)
116cm=2(L+10cm)
116cm=2L+20cm
116cm-20cm=2L
96cm=2L
L=48cm
so,the length of the tower is 48 cm
4. The perimeter of a square that had side 40 cm long is … cm.
Jawaban:
kita jagatuhan. engkau menjaga kita.
Penjelasan dengan langkah-langkah:
supaya tuha menjagakita
5. 2 The perimeter of a rectangular cardboard is 180 cm. The length of the cardboard is 52 cm. Find its breadth.
Jawaban:
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6. The area of a square park is the same as of a rectangular park. If the side of the square park is 60 m and the length of the rectangular park is 90 m, find the breadth ofthe rectangular park.Hint: You've to find the area then perimeter Note: Need Full Explanation in English!
[tex]{ \purple{ \large{ \underline{ \pmb{ \frak{Given : }}}}}}[/tex]
★The area of a square park is the same as of a rectangular park
★ If the side of the square park is 60 m and the length of the rectangular park is 90 m
★ find the breadth of the rectangular park.
[tex]{ \purple{ \large{ \underline{ \pmb{ \frak{ To \: Find : }}}}}}[/tex]
★ The breadth of the rectangular park
[tex]{ \purple{ \large{ \underline{ \pmb{ \frak{ Let's \: understand \: the \: concept : }}}}}}[/tex]
☀️Concept:Now, we have said that the area of square park is equal to the rectangular park. so, we have to find the area of the square park first and then as we know that the area of the rectangular park is the same so, let's find its breadth with the help of he area.
[tex]{ \purple{ \large{ \underline{ \pmb{ \frak{Using \: concept : }}}}}}[/tex]
~ Formula to find the area of a square :
➼ Area of a Square = Side times Side
~ Formula to find the area a rectangle :
➼ Area of a rectangle = Length times Breadth
[tex]{ \purple{ \large{ \underline{ \pmb{ \frak{Full \: solution : }}}}}}[/tex]
~ Now, let's find the Area of the square first Substituting the measurement of its dimension which is 60m using the below mentioned formula
✪ Areaofthesquare=Side×Side
➼ Area of the square = S × S
➼ Area of the square = S²
➼ Area of the square = 60m²
➼ Area of the square = 3600m²
Henceforththeareaofthesquareis3600m²★ We know that,
➼Area of the square = Area of the rectangle
➼ 3600m² = Area of the rectangle
Henceforththeareaoftherectangle= 3600m²~ Now let's find the breadth of the rectangle with the help of its area and the measurement of its length which are 3600m² and 90m respectively Substituting the values in the below mentioned formula.
✪ Areaofarectangle=Length×Breadth
➼ Area of the rectangle = L × B
➼ 3600cm² = 90 × B
➼ B = 3600m²/90m
➼ B = 30m
HenceforththeBreadthoftherectangleis30m[tex]{ \purple{ \large{ \underline{ \pmb{ \frak{Additional \: Information : }}}}}}[/tex]
★ Area of a Rhombus = ½ × D1 × D2
★ Perimeter of a Rectangle = 2(L+ B)
★ Area of a Parallelogram = Base × Hieght
★ Area of a Triangle = ½ × Base × Height
★ Area of a Circle = πr²
★ Perimeter of a Square = 4 × Side
★ Perimeter of a Parallelogram = 2( a + b )
★ Perimeter of a Circle = 2πr
★ Perimeter of a Triangle = Sum of all sides
[tex]{ \purple{ \large{ \underline{ \pmb{ \frak{ Diagrams : }}}}}}[/tex]
❍ Square:
[tex]\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large 60\ m}\put(4.4,2){\bf\large 60\ m}\end{picture}[/tex]
❍ Rectangle:
[tex]\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 90 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 30 m}\end{picture}[/tex]
7. Siti has a rectangular waffle the lenght is 6 cm and width is 2 cm. The perimeter of the waffle is . … cm.
Perimeter
K = 2p + 2l
K = 2(6) cm + 2(2) cm
K = 12 cm + 4 cm
K = 16cm
8. The perimeter of a rectangular TV screen is 150 cm. The ratio of the width to the height is 16:9. Find the area of the screen.
Answer/Jawaban:
1296 cm^2
Explanation :
Given the perimeter is 150 cm, meanwhile the ratio of the width and the height is 16 : 9. Assume the width and the height is 16x and 9x. We can substitute to the perimeter formula :
P = 2(16x + 9x) = 150 cm
<=> 2.25x = 150 cm
<=> 50x = 150 cm
<=> x = 3 cm
So, the width is 16 x 3 cm = 48 cm, meanwhile the height is 9 x 3 cm = 27 cm.
We can conclude that the area of the screen is 48 x 27 = 1296 cm^2.
Penjelasan :
Diketahui kelilingnya 150 cm, sedangkan perbandingan lebar dan tingginya 16 : 9. Misalkan lebar dan tingginya adalah 16x dan 9x. Kita bisa masukkan ke rumus keliling :
P = 2(16x + 9x) = 150 cm
<=> 2.25x = 150 cm
<=> 50x = 150 cm
<=> x = 3 cm
Jadi, lebarnya adalah 16 x 3 cm = 48 cm, sedangkan tingginya adalah 9 x 3 cm = 27 cm.
Kita bisa simpulkan bahwa luas layarnya adalah 48 x 27 = 1296 cm^2.
9. The perimeter of a rectangular field is 52 m. its breadth is 8 m. FIND ITS LENGHT.
Jawaban:
Jawaban :
52Rectangular field
Penjelasan dengan langkah-langkah:
karena yang ditanya panjang nya jadi jawabannya adalah 52
Maaf kalau salah
10. 4. The length of a rectangular field is twice its breadth. If the perimeter is 30 m, findarea of the field.
Penjelasan dengan langkah-langkah:
length = 2 x breadth
perimeter = 30 m
perimeter = 2 x (length + breath)
p = 2 x (l + b)
30 = 2 x (2b + b)
3b = 30/2
b = 15/3
b = 5 m
l = 2b
l = 2 x 5
l = 10 m
Area = l x b
A = 10 x 5
A = 50 m²
11. The area of a rectangular piece of paper is 48 cm2. Its length is 8 cm.(a) Find its breadth.(b) Find the perimeter of the rectangular piece of paper.8 cmArea= 48 cm?
Jawaban:
area = length × breadth
a) 48 cm² = 8 cm × breadth
breadth = 48 cm² ÷ 8 cm
= 6 cm
perimeter = 2 ( length + breadth)
b) 2 ( 8 cm + 6 cm)
= 2 × 14 cm
= 28 cm
perimeter = 28 cm
12. The perimeter of a rectangular laboratory is 64 m. If the length of the laboratory is 23m, find the width of the laboratory.
Jawaban:
Jadi lebar laboratorium tersebut adalah 9 meter
Cara:64 - (2 x 23 = 46) = 18 : 2 = 9 meter
Jadikan Jawaban tercerdas ya agar kapan-kapan saya akan bantu lagi ｡◕‿◕｡
13. 3. The length of a rectangular file is 45 cm, If the breadth of file is 20 cm.what is the area of the rectangular file is ... cm²
Jawaban:
450 cm pangkat 2
Penjelasan:
= 1/2 x a x t
= 1/2 x 20 x 45 (Sistem coret= 2 dan 20 = 10, 10 x 45)
= 450 cm pangkat 2
smoga membantu maaf klo salah :}
14. the perimeter of a rectangular field is 70m and it's length is 15m longer than its breadth. the feild is surrounded by a concrete path of width 5m. find the area of the path.
l1 = b1 + 15
P = 2(l+b)
70 = 2(b+15+b)
70 = 2(2b+15)
70 = 4b + 30
40 = 4b
10 cm = b1
l1 = 15 + 10 = 25 cm
area of path
= A.rectangular 2 - A.rectangular 1
= 35 × 20 - 25 × 10
= 700 - 250
= 450 cm^2
15. the base of a rectangular tank is 135 m2 the volume of the tank is 6.750 m³ therefore the height of the rectangular tank is
Volume of a rectangle = area of base . Height
= H = 6750 / 135
= h = 50 cm
16. The perimeter of the figure is . . . .
Penjelasan dengan langkah-langkah:
Perimeter = keliling
Keliling = 10 + 3 + 5 + 1 + 3 + 1 + 2 + 3 =28m
17. the area of a rectangular carpet is 126 m2. its breath 7m. A. Find its length B. Find the perimeter of the carpet
Jawaban:
A. l = 18 m, and
B. P = 50 m.
Penjelasan dengan langkah-langkah:
DIKETAHUI A rectangular carpet,A = 126 m², andb = 7 m.DITANYA l = ...?P = ...?CARADETERMINE THE LENGTH[tex]A = l \times b \\ 126 = l \times 7 \\ \frac{126}{7} = l \\ 18 \: m = l[/tex]
DETERMINE THE PERIMETER[tex]P = 2(l + b) \\ P = 2(7 + 18) \\ P = 2(25) \\ P = 50 \: m[/tex]
Semogamembantu!
18. The perimeter of figure on the left is....A. 33 cmB. 44 cmC. 55 cmD. 66 cmA rectangular swimming pool has a length of 40 m and breadth 11 m. What is the perimeter of the swimming pool ? Answer : ....
1. Perimeter = (2 x 6.5) + (2 x 10)
= 13 + 20
= 33 cm (A)
2. Perimeter = (2 x 40) + (2 x 11)
= 80 + 22
= 102 m
19. The perimeter of rectangular hall is 72 m. The length of the hall is 3 times its breadth. Find the length of the hall.
length = 3*breadth
perimeter = 2(length + breadth)
72 =2(3*breadth + breadth)
36 = 4 breadth
breadth = 9m
length = 3*9 = 27 m
20. The perimeter of the figure is . . . .
Jawaban:
15Penjelasan dengan langkah-langkah:
lihat gambar di atasKeliling bangun tersebut adalah 15
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