1. Solve the equation |x + 2| = 62. Solve the equation |3x - 2| = 2x + 43. Solve |2x - 1| = |x + 4|tolong, Kak. ini harus sekarang
1. 1. Solve the equation |x + 2| = 62. Solve the equation |3x - 2| = 2x + 43. Solve |2x - 1| = |x + 4|tolong, Kak. ini harus sekarang
Jawaban:
1. |x+2|=6
x+2=6
x= 6-2
x= 4
x+2=-6
x= -6-2
x= -8
maka hp nya adalah x= -8; x= 4
2. |3x-2|= 2x+4
3x-2= 2x+4
3x-2x= 4+2
x= 6
3x-2= -2x-4
3x+2x= -4+2
5x= -2
x= -2/5
maka hp nya adalah x= -2/5; x=6
3. |2x-1|= |x+4|
2x-1= x+4
2x-x= 4+1
x=5
2x-1= -x-4
2x+x= -4+1
3x= -3
x= -3/3
x= -1
maka hp nya adalah x= -1; x=5
2. -1/x=7/2+2/x. Solve the equation
Jawab:
x =
Penjelasan dengan langkah-langkah:
-1/x = 7/2 + 2/x
-3/x = 7/2
1/x = -7/6
x = -⁶/ [tex] _7 [/tex]
3. Solve the equation 2π - x² = 0
Penjelasan dengan langkah-langkah:
penjelasan terlampir di foto
4. 1.Ekspresi |-x2 + 1 | untuk -1≤ x ≤ 3 mempunyai nilai terkecil yaitu ... 2.Solve the following equation: |2x - 3| = 3 3.Solve the following equation: |x +1| = |2x-3|
Jawaban:
maaf cuma jawab no satu
Penjelasan dengan langkah-langkah:
jika mau bertanya lebih lanjut DM IG KITA @barbarboos
5. 8. Solve the equation3^(5x + 2) / 9^(1 - x) = 27^(4 + 3x) / 729
Penjelasan dengan langkah-langkah:
Silahkan di klik gambarnya
6. solve the equation below x^2 = 3x + 2 = 0
Assume that the typo in the right side of x² is a pus (+) symbol.
So,
x² + 3x + 2 = 0
Factorize it.
(x+1)(x+2) = 0
Get some radixes:
x₁ + 1 = 0
x₁ = -1
x₂ + 2 = 0
x₂ = -2
So, the solution of the equations are:
x = {-2,-1}
[tex]\displaystyle x^2+3x+2=0\\x^2+2x+x+2=0\\x(x+2)+1(x+2)=0\\(x+1)(x+2)=0\\\\x+1=0\\x=-1\\\\\text{or}\\\\x+2=0\\x=-2\\\\\boxed{\boxed{S=\{-1,-2\}}}[/tex]
7. solve the equation 3x-y=23 x/3 + y/4 =4
Penjelasan dengan langkah-langkah:
jawaban tertera pada gambar :
x=9 dan y=4
8. Q5. Solve the equation -4(10 + 3x) - (x + 8) = -9
Jawab:
x = -3
Penjelasan dengan langkah-langkah:
-4(10 + 3x) - (x + 8) = -9
[-4.10 + (-4)(3x)] - [x + 8] = -9
[-40 - 12x] - x - 8 = -9
-40 - 8 - 12x - x = -9
-48 - 13x = -9
-48 + 9 = 13x
-39 = 13x
x = -39/13
x = -3
___
Silakan dikoreksi kembali
9. 11. Solve each of the following equations.11(b) 2 - 3.5y – 9.75y2 = 0(a) x25.X + = 04 412. Solve the equation 9x²y2 – 12xy + 4 = 0), expressing yin terms of x.013. Solve the equation x - (2x - 3)2 = -6(x² + x - 2)..BANTU CEPAT
Jawaban:
11.
a) x1 = 1/2, x2 = 5
b) y1 = -2/3, y2 = 4/13
12. dy/dx = -y/x
13. x1 = -21/2, x2 = 1
Maaf Kalau Salah10. Solve the equation=2(3×)-5 1+x=0
1 + x = 0
1 - 1 + x = 0 - 1
x = - 1
2 ( 3x ) - 5
2 ( 3(-1) ) - 5
2 ( -3 ) - 5
-6 - 5
= -11
1+x=0
x=-1
2 (3x) - 5 = 2 (3.(-1)) - 5
= - 6 - 5
= - 11
11. given the functions f(x) = x^2 - x and g(x) = x^2 - 3x - 12 a. solve the equation f(x) = 6 b. solve the equation f(x) = g(x)
Jawaban:
BSOLVETHEEQUATIONF(X)=6Penjelasan dengan langkah-langkah:
MAAFKALAUSALAH12. 2(x-1)+3(x+1)=4(x+4) Solve the equation tolong jawab dengan caranya ya yang lengkap
Jawaban:
(2(x-1)) + (3(x+1)) = 4(x+4)
2x - 2 + 3x + 3 = 4x + 16
5x + 1 = 4x + 16
5x - 4x = 16 - 1
x =15
13. solve the equation below 3 - 2x - x^2 = 0
Use some tricks.
[tex]$\begin{align}3-2x-x^2&=0 \\ \text{Multipty both }& \text{sides by (-1)} \\ (-1)(3-2x-x^2)&=(-1)(0) \\ -3+2x+x^2&=0 \\ x^2+2x-3&=0 \\ (x+3)(x-1)&=0\end{align}[/tex]
The correct x are:
x = {-3,1}
[tex]x^2-x+3x-3=0 \\ \\ x(\frac{x^2}{x}-{x}{x}+3(\frac{3x}{3}-\frac{3}{3})=0 \\ \\ x(x^{2-1}-1)+3(x-1)=0 \\ \\ (x-1)(x+3)=0 \\ \\ \\ x-1=0 \\ \\ x+3=0 \\ \\ x=1 \ dan \ x=3 \\ \\[/tex]
Jadi x∈{1,-3}
14. solve equation (x-3)^2-1=0
Jawab:
=
4
=
2
Penjelasan dengan langkah-langkah: [ x3 [ x3 −
1
=
0
{\col
15. Solve this equationx - 4 = -6
Penjelasan dengan langkah-langkah:
^PLSV^
[tex]x - 4 = - 6[/tex]
[tex]x = - 6 + 4[/tex]
[tex]{ \boxed{ \rm x = - 2}}[/tex]
Jawaban:
x - 4 = -6
x = -2
Penjelasan dengan langkah-langkah:
maaf kalau salah
semoga membantu
16. solve the equation:[tex]2( {3}^{x} ) - {5}^{x + 1} = 0[/tex]
Jawaban:
maaf ka klo salah, trima kasih
17. Pls solve the equation, thank you! (x+1)(x-2)(x-3)>=0
Pertidaksamaan
(x + 1)(x - 2)(x - 3) ≥ 0
Pembuat nol
x + 1 = 0 ---> x = -1
x = 2
x = 3
- - ...(-1) ... ++ ... (2) ... - - ... (3) ... ++
Nilai x yg memenuhi :
-1 ≤ x ≤ 2 atau x ≥ 3jawab
(x+1) ( x-2)(x - 3) ≥ 0
x = - 1 , x = 2, x = 3
garis bilangan
.. (-)...(-1)...(+)..(2)..(-)...(3)..(+)..
daerah HP ≥ 0 (daerah (+) )
Hp -1 ≤ x ≤ 2 atau x ≥ 3
18. solve the equation below ( 3^x ) ( 9 ^2X ) = [tex] \frac{1^3}{9} [/tex]
[tex]$\begin{align}3^x.9^{2x}&=\frac{1^3}{9} \\ 3^x.3^{2(2x)}&=\frac19 \\ 3^x.3^{4x}&=\frac1{3^2} \\ 3^{x+4x}&=3^{-2} \\ 3^{5x}&=3^{-2} \\ 5x&=-2 \\ x&=-\frac25\end{align}[/tex][tex]$\begin{align}(3^x)(9^{2x})~&=~\frac{1^3}{9} \\ \\ (3^x)(3^{4x})~&=~3^{-2} \\ \\ 3^{x+4x}~&=~3^{-2} \\ \\ &\bold{agar~sama~,~maka~nilai~pangkat~harus~sama~:} \\ x+4x~&=~-2 \\ 5x~&=~-2 \\ x~&=~-\frac{2}{5} \end{align}[/tex]
19. 9 Given the functions f(x)= x² - x and g(x)= x² – 3x – 12,asolve the equation f(x) = 6b solve the equation f(x) = g(x).
Penjelasan dengan langkah-langkah:
a.) f(x)=6
=>6=x²-x
x² - x - 6 = 0
(x + 2) (x - 3) = 0
x = -2, and x = 3
b.) f(x) = g(x)
g(x) = 6
=>6=x²-3x-12
=> x² - 3x - 12 - 6
=> x² -3x - 18
(x - 6) (x + 3) = 0
=> x=6,andx=-3
20. 2(x-1)+3(x+1)=4(x+4) Solve the Equation
Jawaban:
2x-2+3x+3=4x+16 ( dikali masuk ke dalam kurung)
5x+1=4x+16 ( pindahkan variabel dengan variabel dan konstanta dengan konstanta)
x=15
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