Sabtu, 19 Maret 2022

How Many Grams Are Equal To 400 Kg


How Many Grams Are Equal To 400 Kg

how many kilo grams are there in a ton​

Daftar Isi

1. how many kilo grams are there in a ton​


Jawaban:

1000 Kilograms

Penjelasan:

A Ton = 1000 Kilograms

Jawaban:

1000 kg in 1 ton. smg membantu^^


2. 5 ounces tapioca,5 grams salt 5000 mg pepper how many grams are their mixture


500 grams of tapioca + 5 grams of salt + 5 grams of pepper = 510 grams

maaf kalau salah


3. 5 ounces tapioca,5 grams salt 5000 mg pepper how many grams are their mixture


1005 gram

Penjelasan dengan langkah-langkah:

5 ounces = 500 gram

5 gram = 5 gram

5000 mg = 500 gram

500+5+500= 1005 gram


4. 1. How many serving size for this product?2.How many grams (g) of fot in 1 serving?3.How many calories of fat in 1 serving?4.How many grams (g) of saturated fat in 1 serving?5.How many total grams (g) of catbohydrate?​


Jawaban:

1.2oz(56g)

2.140 grams

3.180

4.6 grams

5.1 grams

Penjelasan:

#BelajarTerusYa


5. the singapore dollar is equal to how many indonesian rupiah money?


1 SGD is about Rp9.000,-



6. 3. To make a tray of biscuits, Uncle Sam mixes 60 g of flour with every 20 g sugar. How many grams of flour are needed to make 1 kg of biscuits?​


Jawab:

= 5/(3+4+5) x 60

= 5/12 x 60

= 40 kg


7. POINT GEDE! ASAL JAWAB REPORT!1. HOW MANY COOKIES ARE IN A SERVING? 2. HOW MANY SERVING IN A PACKAGE3. HOW MANY COOKIES ARE IN PACKAGE? 4. HOW MANY COOKIES DO YOU HAVE FOR SNACK5. HOW MANY GRAM OF SUGAR PER SERVING6. HOW MANY TEASPOON OF SUGAR PER SERVING (HINT: THERE ARE 4 GRAMS OF SUGAR PER TEASPOOB7. APPROXIMATELY HOW MANY TEASPOONS OF SUGAR ARE IN EACH COOKIE? ​


Jawaban:

Bismillah

1. The following nutrition information is provided by the USDA for one serving (three cookies, 34g) of Oreo cookies. The number of calories in a cookie depends on the type of cookie you eat. Oreo cookies, for example, contain about 53 calories per cookie.

2. "Some small packages of chips, pretzels, cookies, crackers, etc., look like one serving but the label may say it has 2 to 3 servings per package. Many eat the whole thing assuming it is an individual serving package," Koltun explained.

3. Three

4. Three

5. 4 grams off sugar = 1 teaspoon

The AHA suggests an added-sugar limit of no more than 100 calories per day (about 6 teaspoons or 24 grams of sugar) for most women and no more than 150 calories per day (about 9 teaspoons or 36 grams of sugar) for most men.

6. So how much exactly is a gram of sugar? One teaspoon of granulated sugar equals 4 grams of sugar. To put it another way, 16 grams of sugar in a product is equal to about 4 teaspoons of granulated sugar.


8. How many grams of protein is needed to make one gram of muscle ?


Berapa gram protein yang diperlukan untuk membuat satu gram otot?

Protein adalah sebuah molekul struktural yang terdiri dari asam amino, dimana unsur ini tidak dapat diproduksi oleh tubuh kita. Makanan dari hewan biasanya tinggi kandungan protein yang mengandung kandungan jenis asam amino penting.

Mengkonsumsi protein adalah sangat penting bagi tubuh jika kita ingin menaikkan atau mempertahankan otot tubuh kita. Banyak studi yang menyarankan bahwa 1.6 – 2.2 gram per kg berat badan adalah termasuk cukup.  

Pembahasan:

Teks di atas termasuk jenis Descriptive Text dimana penulis mencoba menjelaskan (describe) tentang sesuatu hal, benda, seseorang, sebuah kejadian, lokasi, dan lain-lain.

Descriptive Text terdiri dari 2 bagian:

Identification – Bagian ini biasanya terdapat di awal paragraph yang memberikan informasi  secara garis besar tentang informasi yang akan disampaikan penulis.Description – Bagian ini adalah bagian yang menjelaskan secara detail dan rinci tentang informasi yang dijelaskan sehingga pembaca memahami dan mendapat gambaran tentang informasi tersebut. Bagian Description ini pada umumnya ditulis setelah paragraph Identification.

Berikut ciri-ciri dari Descriptive Text:

Menggunakan Simple Present Tense.Banyak menggunakan kata sifat (adjective).Banyak menggunakan kata kerja penghubung (relating verb seperti is/am/are, has/have, dal lain-lain.

 

Pelajari lebih lanjut:

Penjelasan tentang Descriptive Text https://brainly.co.id/tugas/28185537

Penjelasan tentang Descriptive Text https://brainly.co.id/tugas/5035658

#BelajarBersamaBrainly #SPJ4


9. Acetylene burns in air to for carbon dioxide and water: C2H2 (g) + O2 (g) -----> CO2 (g) + H2O (l) How many grams of CO2 are formed from 25.0 grams of C2H2?


Acetylene burns in air to for carbon dioxide and water:

C2H2 (g) + O2 (g) -----> CO2 (g) + H2O (l)

many grams of CO2 are formed from 25.0 grams of C2H2 is 84,48 grams.

Pembahasan

[tex]\boxed{\boxed{\bold{Stoikiometri~Reaksi}}}[/tex]

[tex]\mathbf{1.~Persamaan~Reaksi }[/tex]

Persamaan reaksi dapat menunjukkan zat-zat pereaksi (reaktan) dan zat hasil reaksi (produk) yang terlibat selama reaksi. Dalam persamaan reaksi setara dapat terlihat adanya koefisien reaksi yang menunjukkan perbandingan jumlah partikel yang yang terlibat dalam reaksi. Maka, dapat disimpulkan perbandingan jumlah partikel zat sama dengan perbandingan jumlah mol zat. Jadi,  

[tex]\boxed{\boxed{\bold{Perbandingan~Koefisien~=~Perbandingan~mol}}}[/tex]

[tex]\mathbf{2.~Pereaksi~Pembatas }[/tex]

Pereaksi pembatas adalah zat pereaksi yang habis bereaksi sedangkan pereaksi yang lainnya berlebih karena terdapat sisa.  

Cara menentukan pereaksi pembatas adalah :

1. Persamaan reaksi harus sudah setara

2. Menentukan mol masing-masing zat pereaksi

3. Membuat MRS (Mula-mula, Reaksi, Setimbang)

4. Meletakkan mol mula-mula setiap zat pereaksi

5. Membagi masing-masing mol zat pereaksi dengan koefisiennya

4. Hasil bagi paling kecil merupakan pereaksi pembatas

[tex]\mathbf{3.~Senyawa~Hidrat~(Air`Kristal) }[/tex]

Senyawa yang mengandung air kristal disebut senyawa hidrat, sedangkan senyawa yang tidak mengandung air kristal disebut senyawa anhidrat. Air kristal merupakan molekul air yang terkandung dalam susunan kristal senyawa.

Contoh :

MgSO4 x H2O             --- >        MgSO4            +         x H2O

Senyawa hidrat/  senyawa anhidrat      kristal/hidrat

senyawa kristal

Menghitung jumlah kristal/hidrat dengan cara :

a. Membuat perbandingan mol antara senyawa anhidrat dibanding kristal/hidrat nya.

b. Besar nya nilai perbandingan dari senyawa anhidrat harus “1”.

[tex]\mathbf{Cara~Menentukan~Jumlah~Mol~(n) }[/tex]

Menentukan dengan massa molekul relatif  

[tex]\boxed{\boxed{\bold{n~=~\frac{gram}{Mr} }}}[/tex]

dengan,  

n = jumlah mol (mol)  

gram = massa (gram)  

Mr = massa molekul relatif  


[tex]\boxed{\boxed{\bold{Diket}}}[/tex]

massa C₂H₂ = 25 gram

Ar C = 12

Ar H = 1


[tex]\boxed{\boxed{\bold{Ditanya}}}[/tex]

massa CO₂


[tex]\boxed{\boxed{\bold{Jawab}}}[/tex]

Menentukan persamaan reaksi setara

C₂H₂ (g) + O₂ (g) ---> CO₂ (g) + H₂O (l)           (reaksi belum setara)

2C₂H₂ (g) + 5O₂ (g) ---> 4CO₂ (g) + 2H₂O (l)           (reaksi setara)

Menentukan Mr C₂H₂

Mr C₂H₂ = 2. Ar C + 2. Ar H

Mr C₂H₂ = 2. 12 + 2. 1

Mr C₂H₂ = 24 + 2

Mr C₂H₂ = 26

Menentukan jumal mol (n) C₂H₂

n C₂H₂ = [tex]\frac{massa}{Mr}[/tex]

n C₂H₂ = [tex]\frac{25}{26}[/tex]

n C₂H₂ = 0,96 mol

Menentukan jumlah mol (n) CO₂

[tex]\boxed{\boxed{\bold{Perbandingan~Koefisien~=~Perbandingan~mol}}}[/tex]

                       2C₂H₂ (g) + 5O₂ (g) ---> 4CO₂ (g) + 2H₂O (l)

Koefisien            2         :       5        :         4         :      2

Mol                    0,96 mol

n CO₂ = 2 x n C₂H₂

n CO₂ = 2 x 0,96

n CO₂ = 1,92 mol

Menentukan Mr CO₂

Mr CO₂ = 1. Ar C + 2. Ar O

Mr CO₂ = 1. 12 + 2. 16

Mr CO₂ = 12 + 32

Mr CO₂ = 44

Menentukan massa CO₂

n CO₂ = [tex]\frac{massa}{Mr}[/tex]

massa CO₂ = n x Mr CO₂

massa CO₂ = 1,92 x 44

massa CO₂ = 84,48 gram


[tex]\boxed{\boxed{\bold{Kesimpulan}}}[/tex]

massa gas CO₂ yang dihasilkan adalah 84,48 gram


[tex]\mathbf{Pelajari~Lebih~Lanjut }[/tex]

Persamaan reaksi https://brainly.co.id/tugas/1036760, https://brainly.co.id/tugas/6024402, https://brainly.co.id/tugas/20903896, https://brainly.co.id/tugas/20937408, https://brainly.co.id/tugas/21127594 Pereaksi pembatas https://brainly.co.id/tugas/9803223 Menentukan mol https://brainly.co.id/tugas/19317569 , https://brainly.co.id/tugas/19322443, https://brainly.co.id/tugas/1010112# Menentukan massa https://brainly.co.id/tugas/19327560 , https://brainly.co.id/tugas/19674518#, https://brainly.co.id/tugas/962227

----------------------------------------------

[tex]\mathbf{Detil~Jawaban }[/tex]

Mapel : Kimia

Bab : Stoikiometri

Kelas : X

Semester : 2

Kode : 10.7.9

Kata kunci :  mol, koefisien reaksi, gram, massa, reaksi pembakaran, C₂H₂, stoikiometri


10. 1. How many serving size for this product?2.How many grams (g) of fot in 1 serving?3.How many calories of fat in 1 serving?4.How many grams (g) of saturated fat in 1 serving?5.How many total grams (g) of catbohydrate?​


Jawaban:

how are you ready to go to track record di dunia yang tidak mau pcrnn ini siapa yk itu pm and


11. 1. How many serving size for this product?2.How many grams (g) of fot in 1 serving?3.How many calories of fat in 1 serving?4.How many grams (g) of saturated fat in 1 serving?5.How many total grams (g) of catbohydrate?​


Jawaban:

1. 2 serving size

2. 16g

3. 140

4. 6g

5. 1g


12. How many grams of gas are present? 8.75 L of C2H4, at 378.3 kPa and 483 K


Bab : Perhitungan dasar kimia

Kelas : 10

Kode : 10.7.8

Kata kunci : gas, gram, tekanan, suhu, ideal

Pertanyaan :

grams of gas are

Pembahasan :

Gunakan persamaan gas ideal

PV = nRT

P = 378,3 Kpa = 3,707 atm

V = 8,75 L

R = 0,082 ltr.atm/mol.K

T = 483 K

sehingga persamaan menjadi

3,707 . 8,75 = n . 0,082 . 483

n (mol) = 0,819

gram C2H4 = n . Mr C2H4

                    = 0,819 . 28

                    = 22,9 gr

Pelajari lebih lanjut

https://brainly.co.id/tugas/5736085

https://brainly.co.id/tugas/10305340



13. Lee bought a 2.79 kg cake. He cut the cake into 9 equal slices and gave away 6 slices to his friends. How many grams of the cake was left?


Penjelasan dengan langkah-langkah:

2.79 kg --->2.790 g

2.790 × 3 ÷ 9

8.370 ÷ 9

930


14. 1. How many grams of NaCl required to prepare each of the following solutions:​


Penjelasan:

Sorry sir, where is the question and the answer choices?


15. how many terms of the progression 50,46,42,... must be taken for its sum to be equal to 0?


Let [tex]S_{n}[/tex] be the sum of sequence up to n terms. since it's a arithmetic sequence, the difference is constant, so
[tex]d=u_{2}-u_{1}\\=46-50\\=-4[/tex]
now using n-term formula, we get
[tex]u_{n}=u_{1}+(n-1)d\\=50+(n-1)\times(-4)\\=50-4n+4\\=54-4n[/tex]
lets use our logic, the sequence is (50,46,42,38,...10,6,2,-2,-6,-10,...,-42,-46,-50,...). the sequence is symmetry to 0
[tex]50+46+42+...+6+2+(-2)+(-6)+...+(-46)+(-50)=(50-50)+(46-46)+...(2-2)=0+0+...+0=0[/tex]
so, when [tex]u_{n}=-50[/tex], the sum is equal to 0. using n-term formula, we get the n
[tex]u_{n}=54-4n\\-50=54-4n\\4n=104\\n=26[/tex]

the other way is using direct formula. here is the derivative:
[tex]S_{n}=u_{1}+(u_{1}+d)+(u_{1}+2d)+...+(u_{1}+(n-1)d)\\=u_{1}\times n+(0\times d+1\times 1+2\times d+...+(n-1)\times d)\\=u_{1}\times n+(0+1+2+...+(n-1))\times d\\=u_{1}\times n+\frac{(n-1)((n-1)+1)}{2}\times d\\=u_{1}\times n+\frac{n(n-1)}{2}\times d\\=\frac{2u_{1}n+n(n-1)\times d}{2}\\=\frac{n(2u_{1}+(n-1)d)}{2}[/tex]

just follow the step below
now, using series formula for arithmetic series, we get
[tex]S_{n}=\frac{n(2u_{1}+(n-1)d)}{2}\\=\frac{n(2\times 50+(n-1)\times(-4))}{2}\\=\frac{n(100-4n+4)}{2}\\=\frac{n(104-4n)}{2}[/tex]

the last step, just substitute Sn by 0
[tex]S_{n}=\frac{n(104-4n)}{2}\\0=\frac{n(104-4n)}{2}\\n=0\vee 104-4n=0\\n_{1}=0\vee n_{2}=26[/tex]Bab Rows and series

50,46,42

initial Value = 50 = IV
different = 46 - 50 = - 4 = D

Un = IV + (n - 1) D
Un = 50 + (n - 1) -4
Un = 50 + -4n + 4
Un = 54 -4n


Un = - 50

Un = 54 - 4n
-50 = 54 - 4n (Both segments are exchanged)
4n = 54 + 50
4n = 104
n = 104/4
n = 26


So,many developmental requirements = 26


16. how many grams ... one kilo is one thousand grams


brp gram ...

satu kg adalah seribu gramhow many grams 
one kilo is thousand grams

Berapa gram ?
satu kilo adalah seribu gram

soory if wrong
maaf kalo salah


17. how many grams of fiber ar in one serving​


Penjelasan:

i don't know, sorry i can't help you


18. How many grams are in 1.2 x 10²⁴ molecules of water?​


Answer

Mass of water = 36 grams

Explanation

Molecules of water is written in formula : H₂O,

to calculate the mass of the water, we should know about realtive molecular mass of water from periodic table :

Mr H₂O = 2 x Ar H + Ar O = 2 x 1 + 16 = 18 g/mole

From Avogadro number ==>

[tex]\boxed{mole\ of\ water\ = \frac{Molecules\ number\ of \ Water}{6,02\ .\ 10^{23} } }[/tex]

mole of water = 1.2 x 10²⁴ /(6.02 x 10²³) = 1.99 mole = 2 mole

Mass of water = mole of water x Mr water = 2 mole x 18 g/mole

= 36 grams of water

Learn More

about Concept of Mole : brainly.co.id/tugas/2623883


19. how many grams of pure copper must be added to 20 grams of an alloy containing 40% copper to produce an alloy containing 60% copper?


20 gr alloy mengandung 40% copper.
Itu berarti jumlah copper = 8 gr
Karena 40/100 x 20 = 8

Untuk membuat alloy nya mengandung 60% copper, itu berarti copper nya harus ditambah 20%, kan? :)
20/100 x 20 = 4 gr

20 % nya kita tambahin dengan 40% yang tadi

8 gr + 4 gr = 12 gr
YEEY, KETEMU

Eh, soalnya gampang ternyata ya?

Semoga jawabannya betul, wkwk.

20. Lee bought a 2.79 kg cake. He cut the cake into 9 equal slices and gave away 6 slices to his friends. How many grams of the cake was left?


Jawaban:

2.79kg = 2,790g

9-6 = 3

9 slices = 2,790g

3 slices = ? g

3/9 × 2,790

= 930

the cake was left 930 grams

semoga membantu:)


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