1. Solve the equation |x + 2| = 62. Solve the equation |3x - 2| = 2x + 43. Solve |2x - 1| = |x + 4|tolong, Kak. ini harus sekarang
1. 1. Solve the equation |x + 2| = 62. Solve the equation |3x - 2| = 2x + 43. Solve |2x - 1| = |x + 4|tolong, Kak. ini harus sekarang
Jawaban:
1. |x+2|=6
x+2=6
x= 6-2
x= 4
x+2=-6
x= -6-2
x= -8
maka hp nya adalah x= -8; x= 4
2. |3x-2|= 2x+4
3x-2= 2x+4
3x-2x= 4+2
x= 6
3x-2= -2x-4
3x+2x= -4+2
5x= -2
x= -2/5
maka hp nya adalah x= -2/5; x=6
3. |2x-1|= |x+4|
2x-1= x+4
2x-x= 4+1
x=5
2x-1= -x-4
2x+x= -4+1
3x= -3
x= -3/3
x= -1
maka hp nya adalah x= -1; x=5
2. -1/x=7/2+2/x. Solve the equation
Jawab:
x =
Penjelasan dengan langkah-langkah:
-1/x = 7/2 + 2/x
-3/x = 7/2
1/x = -7/6
x = -⁶/ [tex] _7 [/tex]
3. Solve the equation 2π - x² = 0
Penjelasan dengan langkah-langkah:
penjelasan terlampir di foto
4. solve equation (x-3)^2-1=0
Jawab:
=
4
=
2
Penjelasan dengan langkah-langkah: [ x3 [ x3 −
1
=
0
{\col
5. solve the equation:[tex]2( {3}^{x} ) - {5}^{x + 1} = 0[/tex]
Jawaban:
maaf ka klo salah, trima kasih
6. Solve the exponential equation for
Jawaban:
x= -4
Penjelasan dengan langkah-langkah:
Itu 1 saat:
(9/8)⁰
3x+12= 0
3x= -12
x= -4
[tex]( \frac{9}{8} ) {}^{3x + 12} = 1 \\ ( \frac{9}{8} ) {}^{3x + 12} = ( \frac{9}{8} ) {}^{0} \\ 3x + 12 = 0 \\ 3x = - 12 \\ x = \frac{ - 12}{3} \\ x = - 4[/tex]
[tex] \: [/tex]
»Detail Jawaban: Mapel: Matematika Kelas: X Materi: Eksponensial#AyoBelajar!
7. 1.Ekspresi |-x2 + 1 | untuk -1≤ x ≤ 3 mempunyai nilai terkecil yaitu ... 2.Solve the following equation: |2x - 3| = 3 3.Solve the following equation: |x +1| = |2x-3|
Jawaban:
maaf cuma jawab no satu
Penjelasan dengan langkah-langkah:
jika mau bertanya lebih lanjut DM IG KITA @barbarboos
8. 2(x-1)+3(x+1)=4(x+4) Solve the equation tolong jawab dengan caranya ya yang lengkap
Jawaban:
(2(x-1)) + (3(x+1)) = 4(x+4)
2x - 2 + 3x + 3 = 4x + 16
5x + 1 = 4x + 16
5x - 4x = 16 - 1
x =15
9. given the functions f(x) = x^2 - x and g(x) = x^2 - 3x - 12 a. solve the equation f(x) = 6 b. solve the equation f(x) = g(x)
Jawaban:
BSOLVETHEEQUATIONF(X)=6Penjelasan dengan langkah-langkah:
MAAFKALAUSALAH10. Q5. Solve the equation -4(10 + 3x) - (x + 8) = -9
Jawab:
x = -3
Penjelasan dengan langkah-langkah:
-4(10 + 3x) - (x + 8) = -9
[-4.10 + (-4)(3x)] - [x + 8] = -9
[-40 - 12x] - x - 8 = -9
-40 - 8 - 12x - x = -9
-48 - 13x = -9
-48 + 9 = 13x
-39 = 13x
x = -39/13
x = -3
___
Silakan dikoreksi kembali
11. solve the equation 3x-y=23 x/3 + y/4 =4
Penjelasan dengan langkah-langkah:
jawaban tertera pada gambar :
x=9 dan y=4
12. Solve the equation=2(3×)-5 1+x=0
1 + x = 0
1 - 1 + x = 0 - 1
x = - 1
2 ( 3x ) - 5
2 ( 3(-1) ) - 5
2 ( -3 ) - 5
-6 - 5
= -11
1+x=0
x=-1
2 (3x) - 5 = 2 (3.(-1)) - 5
= - 6 - 5
= - 11
13. solve the following equation
Jawaban:
solve the following equation
soalnya mana ???
Jawaban:
memecahkan persamaan berikut
14. Pls solve the equation, thank you! (x+1)(x-2)(x-3)>=0
Pertidaksamaan
(x + 1)(x - 2)(x - 3) ≥ 0
Pembuat nol
x + 1 = 0 ---> x = -1
x = 2
x = 3
- - ...(-1) ... ++ ... (2) ... - - ... (3) ... ++
Nilai x yg memenuhi :
-1 ≤ x ≤ 2 atau x ≥ 3jawab
(x+1) ( x-2)(x - 3) ≥ 0
x = - 1 , x = 2, x = 3
garis bilangan
.. (-)...(-1)...(+)..(2)..(-)...(3)..(+)..
daerah HP ≥ 0 (daerah (+) )
Hp -1 ≤ x ≤ 2 atau x ≥ 3
15. solve the equation below x^2 = 3x + 2 = 0
Assume that the typo in the right side of x² is a pus (+) symbol.
So,
x² + 3x + 2 = 0
Factorize it.
(x+1)(x+2) = 0
Get some radixes:
x₁ + 1 = 0
x₁ = -1
x₂ + 2 = 0
x₂ = -2
So, the solution of the equations are:
x = {-2,-1}
[tex]\displaystyle x^2+3x+2=0\\x^2+2x+x+2=0\\x(x+2)+1(x+2)=0\\(x+1)(x+2)=0\\\\x+1=0\\x=-1\\\\\text{or}\\\\x+2=0\\x=-2\\\\\boxed{\boxed{S=\{-1,-2\}}}[/tex]
16. solve the equation below 3 - 2x - x^2 = 0
Use some tricks.
[tex]$\begin{align}3-2x-x^2&=0 \\ \text{Multipty both }& \text{sides by (-1)} \\ (-1)(3-2x-x^2)&=(-1)(0) \\ -3+2x+x^2&=0 \\ x^2+2x-3&=0 \\ (x+3)(x-1)&=0\end{align}[/tex]
The correct x are:
x = {-3,1}
[tex]x^2-x+3x-3=0 \\ \\ x(\frac{x^2}{x}-{x}{x}+3(\frac{3x}{3}-\frac{3}{3})=0 \\ \\ x(x^{2-1}-1)+3(x-1)=0 \\ \\ (x-1)(x+3)=0 \\ \\ \\ x-1=0 \\ \\ x+3=0 \\ \\ x=1 \ dan \ x=3 \\ \\[/tex]
Jadi x∈{1,-3}
17. 2(x-1)+3(x+1)=4(x+4) Solve the Equation
Jawaban:
2x-2+3x+3=4x+16 ( dikali masuk ke dalam kurung)
5x+1=4x+16 ( pindahkan variabel dengan variabel dan konstanta dengan konstanta)
x=15
18. 9 Given the functions f(x)= x² - x and g(x)= x² – 3x – 12,asolve the equation f(x) = 6b solve the equation f(x) = g(x).
Penjelasan dengan langkah-langkah:
a.) f(x)=6
=>6=x²-x
x² - x - 6 = 0
(x + 2) (x - 3) = 0
x = -2, and x = 3
b.) f(x) = g(x)
g(x) = 6
=>6=x²-3x-12
=> x² - 3x - 12 - 6
=> x² -3x - 18
(x - 6) (x + 3) = 0
=> x=6,andx=-3
19. Solve the equation #goodluck
Jadi Himpunan Penyelesaian dari persamaan adalah {60, 180, 300}
20. solve the quadratic equation below
Step by step explanation
_________
Nomor 1
_________
[tex]\begin{aligned}\rm \frac{5x+12}{3x}&=\rm x\\\rm 5x+12&=\rm 3x^2\\0&=\rm 3x^2-5x-12\\0&=\rm (3x+4)(x-3)\\&\bf x=-\frac{4}{3}~atau~x=3\end{aligned}[/tex]
_________
Nomor 2
_________
[tex]\begin{aligned}\rm \frac{20-8k}{k-5}&=\rm 3k\\\rm 20-8k&=\rm 3k^2-15k\\0&=\rm 3k^2-15k+8k-20\\0&=\rm 3k^2-7k-20\\0&=\rm (3k+5)(k-4)\\&\bf k=-\frac{5}{3}~atau~k=4\end{aligned}[/tex]
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