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3 4 X 2 9


3 4 X 2 9

hitunglah: (-3)² + (-9/4)² (2/3)² x (3/4)³ (5/3)² x 9² x (2/3)²​

Daftar Isi

1. hitunglah: (-3)² + (-9/4)² (2/3)² x (3/4)³ (5/3)² x 9² x (2/3)²​


[tex]1)14 \frac{1}{6} [/tex]

[tex] 2)\frac{3}{16} [/tex]

[tex]3)10 {}^{2} \: atau \: 100[/tex]

smoga membantu maaf kalau salah


2. 2. 3/7 x 4/9 = ....3. 1/9 x 9 = ....4. 6 x 2/7 = ....5. 4 1/2 x 9 = ....6. 6 x 6 2/9 = ....7. 4 1/6 x 3/5 = ....8. 4/9 x 3 1/4 = ....9. 3 5/8 x 4 2/5 = ....10. 4 1/3 x 3 1/4 = ....BWNTU GES PR KU BANYAK,BUKAN INI DOANG​


Jawab: 2. 12/63

             3. 1

             4. 12/7

              5.81/2

               6.336/9

               7.75/30

               8.52/36

              9. 648/40

             10. 169/12

2.) 12/63 = 4/21

3.) 1

4.) 12/7= 1 5/7

5.) 81/2 = 40,5 atau 40 ½

6.) 112/3 = 37, 3 atau 37 ⅓

7.) 5/2 = 1½ atau 1,5

8.) 13/9 = 14/9

9.) 319 /10= 31,9 atau 31 9/10

10.) 169/12 = 141/12

semoga membantu ^^


3. =9 x 10^9 ( 3 x 3 )/ 2² = 9 x 10^9 x 9/4 = 81 x 10^9/4 = ?


Jawaban:

81 bangggggggggggggggggggggggggggg


4. 16. Penggunaan Sifat Assiatif yang tepat berikut iniadalah ...O A. (4 + 3) + 2 = 4 + (3 + 2)O B. (4 x 3) + 2 = 4 x (3 + 2)O C. 4x (9 + 3) = (4 x 9 ) + (4 x 3)O D. 1 x 9 = 9 x 1​


Jawaban:

c. 4×(9+3)=(4×9)+(4×3)

Penjelasan dengan langkah-langkah:

semoga membantu


5. 3. Lim √x-3 per x-9= x→94. Lim x-2 per √x+2-2= x→2​


Jawab:

Penjelasan dengan langkah-langkah:

Maaf ya, nulisnya pake pensil


6. 5²2 x 3 x 4 x 18/9 + 3/9


Jawaban:

5² = 5 × 5

5² = 25

= 2 × 3 × 4 × 1

= 6 × 4

= 24

[tex] \frac{8}{9} + \frac{3}{9} = \frac{11}{9} [/tex]

[tex]Sukhoi35[/tex]

Penyelesaian :

5²

= 5 × 5

= 5 + 5 + 5 + 5 + 5

= 10 + 5 + 5 + 5

= 15 + 5 + 5

= 20 + 5

=25

[tex] - - - - - - - - - - - - - - [/tex]

2 × 3 × 4 × 1

= (2 × 3) × 4 × 1

= (6 × 4) × 1

= 24 × 1

=24

[tex] - - - - - - - - - - - - - - [/tex]

[tex] \tt \large \frac{8}{9} + \frac{3}{9} [/tex]

[tex] =\tt \large \frac{8 + 3}{9} [/tex]

[tex] = \tt \large \frac{11}{9} [/tex]

[tex] =\tt \large 1 \frac{2}{9} [/tex]

[tex] - - - - - - - - - - - - - - [/tex]

Kesimpulan:

•Jadi, hasil dari 5² adalah 25.

• Jadi, hasil dari 2 × 3 × 4 × 1 adalah 24.

• Jadi, hasil dari 8/9 + 3/9 adalah 12/9.


7. Bentuk sederhana dari x^2 (√x- ⁴√x^9) adalah.... a.x^-3/2 - x^¼ b.x^-3/2 + x^¼ c.x^-1 - x^9/4 d.x^-1 -x^-9/4 e.x^3/2 +x^¼


x^2  { x^(1/2)  - x^(9/4) }=
= x^2. x^(1/2)  - x^2 . x^(9/4)
= x^(2+1/2)  - x^(2 + 9/4)
= x^(5/2)  - x^(17/4)



8. a. 9^ 6 x 9^10 x 9^5 :9^12=b. (2^3)^4 x (4^3)^2 : (8^2)^3=


a.
[tex] {9}^{6} \times {9}^{10} \times {9}^{5} \div {9}^{12} [/tex]
[tex] {9}^{6 + 10 + 5 - 12} [/tex]
[tex] {9}^{9} [/tex]

b.
[tex]( {2}^{3} )^{4} \times ( {4}^{3} )^{2} \div ( {8}^{2} ) ^{3} [/tex]
[tex] {2}^{3 \times 4} \times {4}^{3 \times 2} \div {8}^{2 \times 3} [/tex]
[tex] {2}^{12} \times {4}^{6} \div {8}^{6} [/tex]
[tex] {2}^{12} \times ( {2}^{2} ) ^{6} \div ( {2}^{3} ) ^{6} [/tex]
[tex] {2}^{12} \times {2}^{2 \times 6} \div {2}^{3 \times 6} [/tex]
[tex] {2}^{12} \times {2}^{12} \div {2}^{18} [/tex]
[tex] {2}^{12 + 12 - 18} [/tex]
[tex] {2}^{6} [/tex]
Semoga membantu:)

9. lim x→3 9-x^2/2√x^2+3-4√3


limit  (9 - x²) /{ 2√(x² + 3)  - 4√3}
x⇒3

     = limit (9 - x²){2√(x² + 3) + 4√3} / {2√(x² + 3) - 4√3} {2√(x² + 3) + 4√3}
        x⇒3
 
     = limit (9 - x²) {2√(x² + 3) + 4√3} / 4(x² + 3) - 16 .3}
        x⇒3
   
     = limit (9 - x²) {2√(x² + 3) + 4√3} / (4x² + 12 - 48)
        x⇒3
 
     = limit (9 - x²) {2√(x² + 3)  + 4√3} / (4x² - 36)
        x⇒3
  
     = limit (9 - x²) {2√(x² + 3) + 4√3} / {4 (x² - 9)}
        x⇒0
 
     = limit { 2√(x² + 3) + 4√3 } / 4
        x⇒3
 
     = {2√(3² + 3) + 4√3} / 4
  
     = (2√12  + 4√3) / 4
      
     = {4√3 + 4√3) / 4
     
     = 8√3 / 4
      
     = 2√3

10. 2 (x + 3) + 3 (x - 4) = 9


Jawaban:

2 (x + 3) + 3 (x - 4) = 9

2x + 6 + 3x - 12 = 9

5x - 6 = 9

5x = 9 + 6

5x = 15

x = 15/5

x = 3


11. 3/9 x 4/2 = n x 3/9 Berapakah n?


n =
[tex] \frac{4}{2} [/tex]
3/9×4/2=n×3/9.jadi,n=4/2 (operasi hitung komutatif/pertukaran)

12. 16. Turunan pertama dari fungsi yang dinyatakan dengan f(x) = (x-5) / (x+4) adalah ... *3 poin9 / (x-5)^2-9 / (x-5)^29 / (x+4)^23 / (x+4)^2-9 / (x+4)^2​


Penyelesaian:

f (x) = (x - 5)/(x + 4)^2

f'(x) = 1 (x + 4) - 1 (x - 5)/(x + 4)^2

f'(x) = x + 4 - x + 5/(x + 4)^2

f'(x) = 9/(x + 4)^2

====================

Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Turunan Fungsi Aljabar

Kode: 11.2.9

KataKunci: turunan pertama


13. (2/3)4 x (2/3)9 =....../artinya per 4 sama 9 itu perpangkatan.tolongin saya


(2/3)pangkat 13.
Karna jika angkanya sama, pangkatnya tinggal dijumlahkan

14. 1. 1/3 x 4/5 ÷16/9 =2. 2 2/3 ÷ 4/9 x 1 6/9 =


1)1/3× 4/5×9/16
»3/20

2)2 2/3 × 9/4 × 1 6/9
»10

Semoga(:)membantu ya

15. 2(x + 3) + 3(x - 4) = 9


2x+6+3x-12=9
5x-6=9
5x=15
x=32(x + 3) + 3 (x-4) =9
2x +6 + 3x -12 = 9
5x -6 = 9
5x = 9+6
5x = 15
x = 3

16. (2^4 x 3^6)^2 : (2^4 x 9^2)^3 =?​


Penjelasan dengan langkah-langkah:

[tex]( { {2}^{4} \times {3}^{6} )}^{2} \div ( { {2}^{4} \times {9}^{2} )}^{3} \\ ({2}^{4 \times 2} \times {3}^{6 \times 2} ) \div ( {2}^{4 \times 3} \times {9}^{2 \times 3} ) \\ ( {2}^{8} \times {3}^{12} ) \div ( {2}^{12} \times {9}^{6} ) \\ ( {2}^{8} \times {3}^{12} ) \div ({2}^{12} \times {( {3}^{2}) }^{6} ) \\ ( {2}^{8} \times {3}^{12} ) \div ( {2}^{12} \times {3}^{12} ) \\ {2}^{8 - 12} \times {3}^{12 - 12} \\ {2}^{ - 4} \times {3}^{0} \\ \frac{1}{ {2}^{4} } \times 1 \\ \frac{1}{16} [/tex]

gambar ke 1 ma gambar ke 2itu dismbng ya! maap kalo salah


17. (2^4 x 3^6)^3 : (4^2 x 9^2)^2 =?​


Jawaban:

(2^4×3^6)^3 ÷(4^2×9^2)^2

=(2^12×3^18)÷(2^4×3^4)^2. Note: 4=2^2

9=3^2

=(2^12×3^18)÷(2^8×3^8)

=2^4×3^10


18. (3^4 x 9)^2 : (27 x 9^-2)^2 ^ = Pangkat



[tex] { ({3}^{4} \times 9) }^{2} \div {(27 \times {9}^{ - 2} )}^{2} \\ = { ({3}^{4} \times {3}^{2} ) }^{2} \div {( {3}^{3} \times { ({3}^{2}) }^{ - 2} )}^{2} \\ = {( {3}^{6} )}^{2} \div {( {3}^{3} \times {3}^{ - 4} )}^{2} \\ = {3}^{12} \div {( {3}^{ - 1} )}^{2} \\ = {3}^{12} \div {3}^{ - 2} \\ = {3}^{10} [/tex]

19. Persamaan lingkaran yang berpusat di P( -3, 4 ) dan jari – jari r = 3 adalah … A.(x + 3)2 + (y + 4)2 = 9 B.(x + 3)2 + (y – 4)2 = 27 (x + 3)2 + (y – 4)2 = 3 (x + 3)2 + (y – 4)2 = 9 (x - 3)2 + (y – 4)2 = 9


Penjelasan dengan langkah-langkah:

Pusat (-3, 4) dan jari-jari (r) = 3

persamaan lingkaran

(x - a)² + (y - b)² = r²

(x - (-3))² + (y - 4)² = 3²

(x + 3)² + (y - 4)² = 9

======================

Detail Jawaban

Kelas : 11

Mapel : Matematika

Bab : Lingkaran

Kode : 11.2.5.1

Kata Kunci : persamaan lingkaran


20. 1 2 (12 4) 2 (9 3) 4 4 3 x x − +  + −


12(12×4)-2(9+3)+4-43

=144×48-18-6-39

=6912-48-18-6-39

=7874-18-6-39

=7856-6-39

=7850-39

=7811


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