find the solution to the system of linear equations x+y=6 dan 2x-y=0
1. find the solution to the system of linear equations x+y=6 dan 2x-y=0
Jawaban:
x+y=6
2x-y=0
_____+
3x =6
x =6/3
x =2
x+y=6
2+y=6
y=6-2
y=4
hp {(x,y)}={(2,4)}
2. Find the solution of the following linear equations system: 2x+3y=20 and7x+2y=53 *
2x+3y= 20.......(1)
7x+2y= 53.......(2)
we multiply (1) by 2 and (2) by 3,
4x+6y= 40.......(1)
21x+6y= 159......(2)
we substract (1) and (2)
4x-21x= 40-159
-17x= -119
x= 7
we substitute x= 7 to (1)
4(7)+6y= 40
28+6y= 40
6y= 40-28
6y= 12
y= 2
so, the solution is:
x= 7
y= 2
3. 3x + 4y = -22y - x = -19 what is the solutions ( x , y ) to the system of equations above?
Jawab:
(x,y)=(3,-8)
Penjelasan dengan langkah-langkah:
Consider the equations
3x + 4y=-23….(1) and 2y - x =-19….(2)
3*(2)=> 6y - 3x = -57
(1) => 4y + 3x =-23
Adding the above equations we get
(6y - 3x) + (4y + 3x)=-57–23
10y = -80
y=-80/10
y= -8
Put the value of y in equation (2) we get
2(-8)-x =-19
-16 - x =-19
-x =-19+16
-x =-3
x= 3
So the solution is (x,y)=(3,-8)
========================================may be usefulglad to help youkeep the spirit[tex]by:asya291006[/tex]
4. What is the area of the triangle shown below
a = 5
b = 5
c = 8
Keliling
= a + b + c
= 5 + 5 + 8
= 18
s = 1/2 x keliling
s = 1/2 x 18
s = 9
Luas
= √(s(s - a)(s - b)(s - c))
= √(9(9 - 5)(9 - 5)(9 - 8))
= √(9 x 4 x 4 x 1)
= √144
= 12 satuan luas
5. p(x-q)=xmake x the subjeCT of the equations
Jawab:
x=qx-c
Penjelasan dengan langkah-langkah:
[tex]\frac{x}{x+c}[/tex]=[tex]\frac{p}{q}[/tex]⇒x=[tex]\frac{p(x+c)}{q}[/tex]
qx= p(x+c)
[tex]\frac{qx}{p}[/tex]=x+c⇒qx-c=x
x=qx-c
6. The mass of rod is 5kg. the rod is attached at the wall using the hinge, as shown the system below. find the tension of the tie rope and force components of the hinge in the system
Jawaban:
pppppppppppppppppppppppppp
7. make x the subject of the equationsa(x+1)=b(x+2)
[tex]\begin{align} a(x+1) &= b(x+2) \\ ax+a &= bx+2b \\ ax-bx &= 2b-a \\ x(a-b) &= 2b-a \\ x &= \frac{2b-a}{a-b} \end{align}[/tex]
a(x+1) = b(x+2)ax + a = bx + 2b
ax - bx = 2b - a
x(a - b) = 2b - a
x = 2b-a/a-b
hope this helps^^
8. The solution to the system of equations 3x-2y=12 and 5x+y=7 is x=p and y =q. The value of 4q+3q is …
Jawaban:
-21
Penjelasan dengan langkah-langkah:
x = p
y = q
solve for x and y
we need to match the x coefficient first, so we can eliminate it and continue.
3x - 2y = 12 (times 5)
5x + y = 7 (times 3)
15x - 10y = 60
15x + 3y = 21
-------------------- (subtract)
-13y = 39
y = 39 ÷ -13
y = -3
then, substitute y with -3 onto one of the equations above.
5x + y = 7
5x - 3 = 7
5x = 7 + 3
5x = 10
x = 2
x = p and y = q
2 = p and -3 = q
the value of 4q + 3q
= 4q + 3q
= 7q
= 7(-3)
= -21
the value of 4q + 3q is -21
9. Roots of the equations x^2 – 3x + 2 = 0 are …
Penjelasan dengan langkah-langkah:
Maaf ya kalau salah nama nya juga manusia pasti punya kesalahan
10. The expression of hope is shown by the sentence
Jawaban:
I hope i got 100 score in my test! Im so nervous!
Penjelasan:
smg membantu:) <3
11. 1.Mention the organ of human! 2.What the function of skeletal system? 3.Mention the part of Respiratory system? 4.Respiratory system is for......... 5.Mention the parts of skeletal system!
1. Brain, heart, liiver, stomach, lungs, pancreas2. -Provides a form to support the body (skeleton formation)
-As a means of passive motion,
3. The airway, the lungs, and the muscles of respiration
12. solve each of the equations (6h+5)(h-1)= -3
(6h+5)(h-1)=-3
6h2-6h+5h-5=-3
6h2-h-5+3=0
6h2-h-2=0
(3h-2)(2h+1)
3h-2=0
3h=2
h=2/3
2h+1=0
2h=-1
h=-1/2
it means h1=2/3, h2=-1/2 maybe wkwk
13. The signature of the letter is shown by sentence
Jawaban:
The signature of the letter is shown by sentence
Tanda tangan surat itu ditunjukkan oleh
kalimat
Semoga Membantu
14. calculate the magnitude of thrust force exerted by each rocket for the four rocket propulsion system shown in the figure the system initial acceleration is 49.65 m/s2 the mass of the system is 2000 kg and the force of friction opposing the motion is 700 N
Jawaban:
Coba kalau ga salah ya ini ahaha,
kan disitu dikasih tau,
" ... the acceleration is 49.65m/s² ... "
berarti nanti percepatan untuk gaya normalnya udah ga pake percepatan gravitasi lagi,
N = m . a = 2000 . 49.65 = 99300N
Nah disitu ada gaya gesek udara,
berarti,
∑Fy = m . a
F - fg = m . a
F = gaya dorong roket ( N )
fg = gaya gesek udara ( N )
F = m . a + fg = 99300 + 700 = 100000N = 100kN
Koreksi ya kalo gua ada salah.
15. find the solution to each of the following system of equations by elimination for example 2x+y=5 and 3x-2y=11
3x-2y=11 |×1
2x+y=5 |×2
⇒3x-2y =11}ini
4x+2y=10}dikurangkan ini
⇒-x=1 ⇔x=-1 dan y = 2x+y=5
2×-1+y =5
-2+y=5
y=7
16. what is the area of the rectangle shown below?
Jawab:
Penjelasan dengan langkah-langkah:
The area= luas yaa
okee berarti sangat gampang kpk!
Luas persegi panjang= lebar x panjang
maka panjang= 5 3/4 =23/4 cm dan lebar=3 cm
L= pxl
= 23/4 x 3
=69/4
=17 1/4 cm atau 17,25 cm
17. Solve each of the following equations 2(x+3)=8
Semoga terbantu.....:)Kelas 7 Matematika
Bab Persamaan Linear
2 (x + 3) = 8
x + 3 = 8/2
x = 4 - 3
x = 1
18. Solve each of the following equations. a. (3x + 2)(4x - 5)
Jawaban:
12x² - 23x + 10
Penjelasan dengan langkah-langkah:
(3x - 2) (4x - 5)
(3x) (4x) - 5 (3x) - 2 (4x) - (2) (-5)
= 12x² - 15x - 8x + 10
= 12x² - 23x + 10
19. p(x-q)=xmake x the subject of the equations
[tex]\begin{align} p(x-q) &= x \\ px-pq &= x \\ px-x &= pq \\ x(p-1) &= pq \\ x &= \frac{pq}{p-1} \end{align}[/tex]
20. What is the area of the right triangle shown below
ANSWER:
60.
Penjelasanya :
(theorema phytagoras) a=[tex]\sqrt{b^{2} -c^{2} }[/tex]
a= 17[tex]\sqrt{17^{2}-8^{2} } = \sqrt{289-64}[/tex]
a=[tex]\sqrt{225} =[/tex]15
(the area of the right triangle) :
1/2 x a x h
1/2 x 8 x 15
= 60
ur welcome:)
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